# Talk:Field of View

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<math>FoV = 2 * atan \frac{35}{2 * Focal Length} </math> | <math>FoV = 2 * atan \frac{35}{2 * Focal Length} </math> | ||

− | The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should | + | The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should note that "Focal length" is in mm. But more accurate is: |

<math>FoV = 2 * atan \frac{35 mm}{2 * Focal Length} </math> | <math>FoV = 2 * atan \frac{35 mm}{2 * Focal Length} </math> | ||

Should I just edit this into the main page, or should some discussion be held first? -- REW. | Should I just edit this into the main page, or should some discussion be held first? -- REW. |

## Revision as of 23:17, 10 June 2009

in the formula

The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should note that "Focal length" is in mm. But more accurate is:

Should I just edit this into the main page, or should some discussion be held first? -- REW.