Difference between revisions of "Talk:Field of View"

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<math>FoV = 2 * atan \frac{35}{2 * Focal Length} </math>
 
<math>FoV = 2 * atan \frac{35}{2 * Focal Length} </math>
  
The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should not that "Focal length" is in mm. But more accurate is:  
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The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should note that "Focal length" is in mm. But more accurate is:  
  
 
<math>FoV = 2 * atan \frac{35 mm}{2 * Focal Length} </math>
 
<math>FoV = 2 * atan \frac{35 mm}{2 * Focal Length} </math>
  
 
Should I just edit this into the main page, or should some discussion be held first? -- REW.
 
Should I just edit this into the main page, or should some discussion be held first? -- REW.

Revision as of 21:17, 10 June 2009

in the formula

FoV=2*atan{\frac  {35}{2*FocalLength}}

The "35" should be some "length" because it is divided by a length, and should become unitless. Of course the length is the size of a standard negative: 35mm. If you want to "ignore units" as most americans like to do, it should note that "Focal length" is in mm. But more accurate is:

FoV=2*atan{\frac  {35mm}{2*FocalLength}}

Should I just edit this into the main page, or should some discussion be held first? -- REW.